who strong advocated piece wage system​

Explanation:

refer in this attachmeant

ʜᴀᴘᴘʏ ɴᴇᴡ ʏᴇᴀʀ

he say s that 1 condition you have get nice marks

2 condition do not touch phone for 2 days i will agree

And about dialogues i will request for the movie like

please dad can you take me for the movie and tell dad tells that 1 and 2 condition which i clearly told at the beginning . May be it is right or wrong but thanks for asking me And

A VERY VERY HAPPY NEW YEAR

Answer:

यश आणि अपयश एकाच नाण्याच्या दोन बाजू आहेत. दोन्हीचे दायित्व स्विकारण्यासाठी मन खंबीर ठेवण्यासाठी आपण साहाय्य करा. आपल्या अपत्याना कोणत्याही गोष्टी तर्कशुद्ध, ज्ञानरचनात्मक वृत्तीने आत्मसात करण्यास प्रोत्साहन द्या. आपल्या जीवनशैलीला अनुसरून केलेला सारासार विचार व अनुभव यातून सुजाण पालकत्व स्वीकाराल अशी अपेक्षा आहे.

Answer:

यासाठीचे जाणतेपणाने होणारे सर्व तऱ्हेचे प्रयत्न म्हणजे सुजाण पालकत्व होय. मुलाचा पालक हा त्याचा मालक नसून एक नैसर्गिक प्रेरणेने निर्माण केलेला सुजाण विश्वस्त असतो. असे माझे प्रामाणिक मत आहे. मूल जन्माला आल्यानंतर त्या मुलाची वाढ आणि विकास चांगल्या प्रकारे व्हावा; अशी प्रत्येक पालकाची इच्छा असते.

Explanation:

Hope it is helpful

Explanation:

First we need to calculate:

i) No. of subshells ii) No. of orbitals iii) No. of elements

Formula to calculate no. of subshell

1) No. of period is even :

2

(n+2)

2) No. of period is odd :

2

(n+1)

∴

2

(n+2)

⇒n=2

Thus no. of orbitals in various subshell are:

For n=2 we have only s & p orbitals

s has 1 orbital

p has 3 orbital

∴ no. of orbital =4

It is given that each orbital can have a maximum of 3 electrons.

Thus maximum no. of electrons =4×3=12

Hence, the no. of elements = 12

Answer:

Hope it will help you

plz plz plz I'm in need plz

Step-by-step explanation:

Total cost = 498.96 Rs. => Area whitewashed = 249.48 Rs. And according to the question, the area whitewashed is Curved surface area of hemisphere. => 523.908 m³ (approx.)

[tex] \star \; {\underline{\boxed{\pmb{\red{\frak{ \; Given \; :- }}}}}} [/tex]

• Cost of white - washing = Rs.4989.60
• Rate of white - washing = Rs.20

[tex] \\ \\ [/tex]

[tex] \star \; {\underline{\boxed{\pmb{\blue{\frak{ \; To \; Find \; :- }}}}}} [/tex]

• Inside surface area of the dome = ?
• Volume of the air inside the dome = ?

[tex] \\ \\ [/tex]

[tex] \star \; {\underline{\boxed{\pmb{\orange{\frak{ \; SolutioN \; :- }}}}}} [/tex]

[tex] \maltese [/tex] Formula Used :

• [tex] {\underline{\boxed{\pmb{\sf{ CSA{\small_{(Hemisphere)}} = 2 \pi {r}^{2} }}}}} [/tex]

• [tex] {\underline{\boxed{\pmb{\sf{ Volume{\small_{(Hemisphere)}} = \dfrac{2}{3} \pi {r}^{3} }}}}} [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] How to Calculate :

[tex] \longrightarrow [/tex] Here, we can Calculate the Surface Area by dividing the Cost with the Rate . And for calculating the Air sinsid the dome we need to calculate the Volume . As we know for calculating it we should get the Radius first .So, Let's Solve :

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Calculating the Surface Area :

[tex] {\longmapsto{\qquad{\sf{ Surface \; Area = \dfrac{ Cost }{Rate} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Surface \; Area = \dfrac{ 4989.60 }{20} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Surface \; Area = \dfrac{ 498960 }{20 \times 100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Surface \; Area = \cancel\dfrac{ 498960 }{2000} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\pink{\sf{ Surface \; Area = 249.48 \; {m}^{2} }}}}}}}} [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Calculating the Radius :

[tex] {\dashrightarrow{\qquad{\sf{ CSA = 2 \pi {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 249.48 = 2 \times \dfrac{22}{7} \times {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 249.48 \times 7 = 2 \times 22 \times {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 1746.36 = 44 \times {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ \dfrac{1746.36}{44} = {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ \cancel\dfrac{1746.36}{44} = {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 39.69 = {r}^{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ \sqrt{39.69} = r }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\purple{\sf{ Radius = 6.3 \; cm }}}}}}}} [/tex]

[tex] \\ [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Calculating the Volume of air :

[tex] {\implies{\qquad{\sf{ Volume = \dfrac{2}{3} \pi {r}^{3} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \dfrac{2}{3} \times \dfrac{22}{7} \times {6.3}^{3} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \dfrac{2}{3} \times \dfrac{22}{7} \times \bigg( {\dfrac{63}{10}} \bigg)^{3} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \dfrac{2}{3} \times \dfrac{22}{\cancel7} \times \dfrac{\cancel{63}}{10} \times \dfrac{63}{10} \times \dfrac{63}{10} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \dfrac{2}{3} \times 22 \times \dfrac{9}{10} \times \dfrac{63}{10} \times \dfrac{63}{10} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \dfrac{1571724}{3000} }}}} \\ \\ \\ \ {\implies{\qquad{\sf{ Volume = \cancel\dfrac{1571724}{3000} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\red{\sf{ Volume = 523.9 \; {m}^{3} \; \bigg\lgroup Approx. \bigg\rgroup }}}}}}}} [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Therefore :

❛❛ Surface Area of the Dome is 249.48 cm² and the Volume of air inside the dome is 523.9 cm³ . ❜❜

[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]