In a contract of guarantee, the liability of a surety is Options O Secondary O Primary O Does not arise O None of the above

Answer:

1. DIAMETER
2. 90°
3. ARC
4. AO AND OC
5. 8^2+6^2=64+36=√100=10^2

• SO THE AREA OF ABC IS
• √12(4)(6)(2)
• √2*3*2*2*2*2*3*2
• 2*2*2*3
• 24cm^2

Step-by-step explanation:

Answer:

• The line AOC is diameter of the circle with centre O.
• Angle ABC is right angle i.e. 90⁰ .
• Area AMB is arc of circle with centre O.
• The radius of circle with centre O is 5 units .
• The area of ∆ ABC is 24 sq. units.

Step-by-step explanation:

PART 1 :

• Line AOC is a straight line which passes through centre and intersect the circle at two points A and C.
• Hence, it is diameter of the circle with centre O.

PART 2 :

• The inscribed angle theorem states that: " An angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle. "
• Angle AOC subtends 180⁰ at the centre of the circle and angle ABC is half of the angle subtended at the centre.
• Angle ABC is :

[tex] \frac{ {180}^{0} }{2} = {90}^{0} [/tex]

• Hence, Angle ABC is a right angle.

PART 3 :

• Area AMB is the arc of the circle with centre o.

PART 4:

• From geometry of the figure ABC, it is evident that ∆ABC is a right angled triangle with right angle at B.
• By Pythagoras theorem:

(AB)² + (BC)² = (AC)²

• Given that AB = 8 cm and BC = 6 cm.
• This gives AC =

[tex] \: \: \: \: \: \: \: \: = \sqrt{ {8}^{2} + {6}^{2} } \\ \: \: \: \: \: \: \: = \sqrt{ 64 + 36 } \\ = \sqrt{100} \\ = 10 \: cm[/tex]

• AC is the diameter of the circle with centre O. Radius of the circle is

[tex] \frac{10}{2} = 5 \: cm[/tex]

PART 5 :

• ∆ ABC is a right angled triangle with right angle at B.
• Base of triangle = 6 cm
• Height of triangle = 8 cm
• Area of triangle is given by :

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 8 \times 6 \\ = 24 \: sq \: cm[/tex]

Hence, area of ∆ ABC is 24 sq. cm .

Answer:

The ares is 154cm^2

Step-by-step explanation:

Use the formula of area of circle

Area= pi r^2

where pi=3.14 and r is radius of circle.

Answer:

Area of circle is [tex]154 \ cm ^{2}[/tex] .

Step-by-step explanation:

To find : area of circle  

Given : radius of circle is [tex]7\ cm[/tex] .

Solution :

• As per given data w know that radius of circle is [tex]7\ cm[/tex] .
• We use following formula to find area of circle , by substituting the value of [tex]\pi[/tex] and [tex]r[/tex] .
• Area of circle [tex]$=\pi r^{2}$[/tex]

                               [tex]= \frac{22}{7} \times (7 )^{2} \\\\= 22\times 7\\\\= 154\ cm ^{2}[/tex]

Note :

Question for above solution is : what is the area of circle having radius

7 cm ?

I would likewise respond as Valli did on the grounds that I would believe myself to be adequately dependable. Valli believed that she could deal with herself thus, she detested being hindered by seniors.

• In this story, the creator is attempting to introduce the world as seen according to a youngster's point of view.
• The fundamental person of this story is an eight-year-old young lady Valli who lives close to a bus station in a town. Valli fosters a longing to partake in a ride on the transport.
• For this reason, she wants to decrease her costs so she can set aside sufficient cash for the two-way fair.
• While on her excursion, Valli doesn't need anyone's assistance and needs to feel free. She partakes in all of her excursions to the town.
• However, she is cautious enough not to get off the transport in the obscure territories. On her return venture, a miserable mishap ruins her mindset however she simply hushes up about it.
• In this manner, she needs to investigate more and wishes to go for one more ride later on.

my reaction will be same

explain।।

i would think myself to be responsible enough as there are no home person with me .I could take care of myself

Answer:

1.5 moles

Explanation:

Moles=  

molecular weight

Weight

​

Molecular weight of O  

2

​

=32g/mol

Moles=  

32

48

​

 =1.5 moles

Given,

The volume of O₂ gas at STP = 48L

To find,

The number of moles of O₂ at given conditions

Solution,

At STP, the pressure is 1 atm and the temperature is 273K. The proportionality constant, R, is equal to 0.0821 [tex]\frac{L * atm}{mol * K}[/tex]

Now, using the ideal gas law equation,

P × V = n × R × T

where,

• P = Pressure (atm)
• V = Volume (litre)
• n = Number of moles
• R = Universal gas constant ([tex]\frac{L * atm}{mol * K}[/tex])
• T = Temperature (Kelvin)

Further, rearranging the ideal gas equation to get the number of moles

⇒ n = [tex]\frac{PV}{RT}[/tex]

Inserting values into the equation,

⇒ n = [tex]\frac{(1)(48) }{(0.0821)(273)}[/tex]

⇒ n = 2.14 moles

Hence, 48 litres of O₂ at STP = 2.14 moles.