Given,
Mass of the vehicle = 100 kg.
Initial velocity (u) = 5 m/sec
Final Velocity (v) = 0 m/sec
Time taken to stop it (t) = 1/10 sec
To Find,
Given the initial conditions, the required fore in the opposite direction to stop the car.
Solution,
We can solve this numerical by the following process,
We know F=m*a
where F= The amount of applied force
m= mass of the vehicle
a= acceleration of the vehicle
(Here all of the physical quantities are in SI units, So we do not have to do any unit conversion.)
Here, [tex]a=\frac{v-u}{t}\\ a=\frac{0-5}{\frac{1}{10} }\\a=(-5)*10\\a=-50[/tex]
Hence, acceleration is -50 [tex]m/s^2[/tex]
Therefore, Required force, F=m*a
F = (100*(-50))
F = -5000 N
The negative sign signifies that the required force is applied in the opposite direction.
Hence, the required force is -5000 N.