[tex] \dag \; {\underline{\boxed{\pmb{\orange{\frak{ \; Given \; :- }}}}}} [/tex]
- Principal = Rs.4000
- Rate = 7 %
- Time = 3 years
[tex] \\ \\ [/tex]
[tex] \dag \; {\underline{\boxed{\pmb{\purple{\frak{ \; To \; Find \; :- }}}}}} [/tex]
[tex] \\ \\ [/tex]
[tex] \dag \; {\underline{\boxed{\pmb{\red{\frak{ \; SolutioN \; :- }}}}}} [/tex]
[tex] \maltese [/tex] Formula Used :
- [tex] {\underline{\boxed{\pmb{\sf{ S.I = \dfrac{ P \times R \times T }{100} }}}}} [/tex]
- [tex] {\underline{\boxed{\pmb{\sf{ Amount = Principal + S.I }}}}} [/tex]
Where :
- S.I = Simple Interest
- R = Rate
- T = Time
- P = Principal
[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]
[tex] \maltese [/tex] Calculating the Simple Interest :
[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ P \times R \times T }{100} } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 7 \times 3 }{100} } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 21 }{100} } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{84000}{100} } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \cancel\dfrac{84000}{100} } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \longmapsto \; \; {\underline{\underline{\pmb{\pink{\sf{ Simple \; Interst = ₹ \; 840 }}}}}} \end{gathered} [/tex]
[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]
[tex] \maltese [/tex] Calculating the Amount :
[tex] \begin{gathered} \dashrightarrow \; \; \sf { Amount = Principal + Simple \; Interst } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \dashrightarrow \; \; \sf { Amount = 4000 + 840 } \\ \end{gathered} [/tex]
[tex] \begin{gathered} \dashrightarrow \; \; {\underline{\underline{\pmb{\green{\sf{ Amount = ₹ \; 4840 }}}}}} \end{gathered} [/tex]
[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]
[tex] \maltese [/tex] Therefore :
❛❛ Rishabh had to pay ₹ 4840 to clear the debt . ❜❜
[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]
