In an asexually reproducing species, if a trait X exists in 5% of a population and trait Y exists in 70% of the same population, which of the two trait is likely to have arisen earlier? Give reason.

Answer:

The weight of Guddy's school bag is 1 kg.

Step-by-step explanation:

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Information provided with us:

➪ The bag contain 4 books of 100 g each and 3 books of 200 g each

✰ What we have to calculate ༄

• ➪ The required total weight of bag in kg

✰So ༄

➪ The weight of 4 books of 100 g each

[tex]\implies \sf \:4 \times 100 \: g [/tex]

[tex]\implies \sf \:400 \: g [/tex]

➪ The weight of 3 books of 200 g each

[tex]\implies \sf \: 3 \times 200 \: g[/tex]

[tex]\implies \sf \:600 \: g [/tex]

✰Therefore ༄

➪Total weight of all books

[tex]\implies \sf \: 600 \: g + 400 \: g[/tex]

[tex]\implies \sf \: 1000 \: g[/tex]

✰ We know that ༄

[tex]\clubsuit \: \rm 1 \: kg \: = 1000 \: gram [/tex]

➪ So Convert 1000 gram into kg by dividing it by 1000

[tex] \rm \implies \: 1000 \div 1000[/tex]

[tex] \longrightarrow\bigstar \: \: \sf\boxed{\bold{\orange{ 1 \: kg}}}\: \: \: \bigstar\\[/tex]

✰Therefore ༄

➪ The required total weight of bag is

[tex] \longrightarrow\bigstar \: \: \sf\boxed{\bold{\pink{1\:kg }}}\: \: \: \bigstar\\[/tex]

Hogalala was early man language

Answer:

hogalala was an ancient Egypt language in that time of people communicate with others

Given:

Distance= 690 metres

Angle of elevation= 60°

Gravity (g)= 10 m/s²

To Find:

Initial velocity (V₀)

Solution:

For solving this question, we are going to use the horizontal range formula of projectile motion.

To find the maximum horizontal displacement, we consider the "y" component of the displacement equation to be zero,

⇒y= tanθ. x - [tex]\frac{g}{2u^{2}cos^{2}θ }[/tex]. x²

⇒0= tanθ. x - [tex]\frac{g}{2u^{2}cos^{2}θ }[/tex]. x²

⇒ Range =  u²sin2θ/g

[ u= Initial velocity, θ= angle of elevation]

[As all the quantities are in the S.I unit, no conversion is needed.]

Thus, now substituting the given values in the equation, we get,

⇒ 690= [u² × sin (2×45°)] / 10

⇒ 690= [u² × sin 90°] / 10

⇒ 690= u²/10                    ∵ [ sin 90°=1]

⇒ 690× 10= u²

⇒ √6900 = u

⇒ u= 83.066 m/sec

Hence, the Initial velocity (V₀) is 83.066 m/sec.

Answer:

There are two types of files. There are Program files and Data Files. Program files, at heart, can be described as files containing software instructions. Program files are then made up by two files called, source program files and executable files. Source program files contain the original form of instructions from the creator. These are then translated in executable files so the processor can interpret them and carry out the function of the file. The Other type of main file is data files. These are basically to hold data. These are not like program files in which they actually carry out a function on the computer. Rather they contain information that is to be acted on by the program files. There are they types of files that make up data files. These are Graphic Files, Audio files and Animation/Video files. Graphic files can easily be thought of, of the pictures you see. Audio Files are the music files you listen to. Animation/Video files are the movies or clips that you watch on your computer.

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