Accountancy begins where __________ ends ? a)Srutiny b) Auditing c) Book keeping d) Transaction

Answer:

Osmotic pressure

Explanation:

Osmotic pressure is responsible for maintaining the turgidity of the guard cells. Turgidity is the point at which the membrane of the cell pushes against the cell wall, this takes place when the turgor pressure is high.

Answer:

osmotic pressure

Explanation:

it is responsible for maintaing the turgidity of the cells

Answer:

Norman man respires 14-18 times per minute. If the CO2 concentration in blood increases, the rate of breathing also increases. When CO2 is dissolved in the blood, then blood becomes slightly acidic.

Answer:

Step-by-step explanation:

TAKE X=1, Y=2, Z=3...

THEN,

I = 18 , S=8  IS=26

W=4, A=26, S=8  WAS=38

LIKEWISE,

A=26, R=9, E=22 ⇒ 26+9+22 = 57 ; ARE=57

Answer:

Therefore, ARE = 57.

Step-by-step explanation:

Given that IS = 26, WAS = 38,

We have to find the value of ARE.

The Alphabets are A , B, C, D, ................, X, Y, Z.

                                1, 2, 3, 4, ................, 24, 25, 26.

(or)                          26,25,24,23, .............., 1, 2,3.

Now take A = 26, I = 18, S = 8, W = 4, S = 8, R = 9

IS = 18+8 = 26

WAS = 4+26+8 = 38

ARE = 26+9+22 = 57

Therefore, ARE = 57.

Answer:

Maybe because,

1 + 1 + 5 + 7 + 2 ( adding the numerator)

2 + 3 + 6 + 6 + 2 ( adding denominator)

answer : - 16 / 19

( so they must have put 6 instead )

Therefore, 19 / 6

The next term in the series is [tex]\frac{19}{6}[/tex]

Step-by-step explanation:

Given series ,

[tex]\frac{1}{2} ,\frac{1}{3} ,\frac{5}{6} ,\frac{7}{6} , 2[/tex]

- We have to find the next term in series.

To find the next term we first have to observe the pattern which is followed here.

=> The pattern followed is that a number is the sum of pervious 2 numbers.

It can be mathematically written as ,

[tex]n^{th} \ term = (n-1)^{th} \ term + (n-2)^{th} \ term[/tex]

=> Let us verify the pattern in the series,

[tex]3^{rd} \ term = 2^{nd} \ term + 1^{st} \ term[/tex]

[tex]\frac{5}{6} =\frac{1}{2} +\frac{1}{3} \\\\Taking \ LCM \ as \ 6\\\\\frac{5}{6} =\frac{3+2}{6} \\\\\frac{5}{6} =\frac{5}{6} \\\\[/tex]

Hence the pattern is verified.

=> Now finding the next term in the series,

[tex]6^{th} \ term = 5^{th} \ term + 4^{th} \ term[/tex]

[tex]6^{th} \ term =\frac{7}{6} +2 \\\\Taking \ LCM \ as \ 6\\\\\ 6^{th} \ term =\frac{7+12}{6} \\\\\ 6^{th} \ term =\frac{19}{6} \\\\[/tex]

Hence the next term is [tex]\frac{19}{6}[/tex]