A vessel contains 16 litres of pure spirit. From this vessel 2 litres of spirit is replaced with 2 litre of water. Subsequently, 2 litres of the mixture is again replaced with 2 litres of'water and this process is repeated one more time. How much spirit is now left in the vessel?​

Answers 1

The volume of spirit left in the vessel is 10.7l.

Given:-

The volume of Pure spirit (v) = 16l

The volume of water replaced (vw) = 2l

The process is repeated = 3 times

To Find:-

The volume of spirit left in the vessel.

Solution:-

You can simply find out the volume of spirit left in the vessel by using the following procedure.

As

The volume of Pure spirit (v) = 16l

The volume of water replaced (vw) = 2l

The process is repeated = 3 times

The volume of spirit left in the vessel (vs) =?

According to the formula,

The volume of spirit left in the vessel =

[tex]vs = v( { \frac{v - vw}{v} )}^{3} [/tex]

[tex]vs = 16 \times ( { \frac{16 - 2}{16}) }^{3} [/tex]

[tex]vs = 16 \times { (\frac{14}{16}) }^{3} [/tex]

[tex]vs = 16 \times \frac{2744}{4096} [/tex]

[tex]vs = \frac{43904}{4096} [/tex]

[tex]vs = 10.7l[/tex]

Hence, The volume of spirit left in the vessel is 10.7l.

#SPJ5

If you know the answer add it here!

Can't find the answer?

Log in with Google

or

Forgot your password?

I don't have an account, and I want to Register

Choose a language and a region
How much to ban the user?
1 hour 1 day 100 years