Subject:
MathAuthor:
fabianbarrettCreated:
1 year agoGiven:
Let us assume we have two numbers. x is a small number and y is a large number. 4 times the x is less than 3 times the y by 5. If the sum of (x and y) is greater than 6 times the difference of (x and y) by 6.
To Find:
What is the value of x and y?
Solution:
First, we will need to frame a linear equation with two variables x and y, the first condition is given as 4 times the x is less than 3 times y by 5 which can be framed as,
3y-4x=5 -(1)
And the second condition is given as the sum of (x and y) is greater than 6 times the difference of (x and y) by 6 which can be framed as
6(x+y)-(x-y)=6
7y+5x=6 -(2)
Now we will solve these two equations by multiplying the first equation by 5 and the second equation by 4 and then adding both the equations,
5(3y-4x)+4(7y+5x)=25+24
43y=49
y=49/43
Now substituting values of y in equation 1 to find the value of x we have,
[tex]3*\frac{49}{43} -4x=5\\x=\frac{-17}{43}[/tex]
Hence, the value of x and y is -17/43 and 49/43 respectively.
Author:
c-dawggytj
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2Value of x = 43 and y = 59
Given:
Create first equation using 4 times the x is less then 3 times the y by 5
4x = 3y - 5
=> 4x - 3y = -5 Eq1
Step 2:Create second equation using sum of (x and y) is greater then 6 times the difference of (x and y) by 6 and simplify
x + y = 6(y - x) + 6 ( y - x taken as y is larger)
x + y = 6y - 6x + 6
=> 7x - 5y = 6 Eq2
Step 3:5 * Eq1 - 3 * Eq2 and solve for x
20x - 15y -21x +15y = -25 - 18
=> -x = -43
=> x = 43
Step 4:Substitute x= 43 in Eq1 and solve for y
=> 4(43) - 3y = -5
=> 172 - 3y = -5
=> -3y = -177
=> y = 49
Value of x = 43 and y = 59
Author:
anthony991
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